The Structural Miracle II
The word sums ranked.
Why rank the word sums? The concept of first and last is not just of when or where something appears, but also of magnitude.
a) New rank b) Original order c) Greatest to least d) Least to greatest a) 1 2 3 4 5 6 7 8 9 10 11 b) 317 26 26 31 254 120 221 131 208 72 447 c) 680 456 447 409 351 340 322 317 254 221 208 d) 26 26 29 31 31 62 72 72 100 100 102 a) 12 13 14 15 16 17 18 19 20 21 22 b) 340 72 191 351 126 456 29 161 31 165 184 c) 191 184 165 161 131 126 126 120 106 106 102 d) 102 106 106 120 126 126 131 161 165 184 191 a) 23 24 25 26 27 28 29 30 31 32 33 b) 126 409 100 102 106 62 102 100 680 106 322 c) 102 100 100 72 72 62 31 31 29 26 26 d) 208 221 254 317 322 340 351 409 447 456 680
62.1Two words have the sum of 126. In the original passage, they were the 16th and 23rd words. Whether ranked from greatest to the least, or from the least to the greatest these two words remain in the same positions.
62.1.1126 = 7 x 3 x 3 x 2 (a 1 in 7 chance)
62.1.2The positions of 126 from line c: 17 + 18 = 35 (5 x 7 SF: 12 = 2 x 2 x 3 SF: 7).
62.1.3New rank: 16 + 17 = 33 (matches the number of words in the passage)
62.1.4Original positions of 126: 16 + 23 = 39 = 13 x 3 (a factor of God’s Name)
62.2YHWH's numbers are 10-5-6-5. Counting through the ranked words using these numbers:
a) Letter: 10 5 6 5 b) Count: 10 15 21 26 c) Greatest: 221 161 106 72 d) Least: 100 120 184 317
62.2.1The sum of the words in row d): 721 = 7 x 103.
62.2.2The sum of the words in row c): 560 = 7 x 5 x 2 x 2 x 2 x 2.
62.2.3And of course, the greatest and least all together: 560 + 721 = 1281 = 7 x 3 x 61
62.3From the table, the sum of the words in the first and last columns together: 2051 = 7 x 293.
63.The number of times a particular digit appears in the word sums is given in the chart below.
a) Digit b) Number of appearances a) 1 2 3 4 5 6 7 8 9 0 b) 22 17 7 7 4 11 4 3 3 13
63.1The numbers row b) have a total of 14 digits.
63.2Only digits 3 and 4 appear seven times each. 3 + 4 = 7.
63.3The number of digit appearances points out ten different words.
Appearances: 22 17 7 7 4 11 4 3 3 13 Word found: 184 456 221 221 31 447 31 26 26 72
Total: 1715 = 7 x 7 x 7 x 5 SF:26 = 13 x 2
63.4The number of digit appearances can be used to count through the words:
Appearances: 22 17 7 7 4 11 4 3 3 13 Count: 22 6 13 20 24 2 6 9 12 25 Word found: 184 120 72 31 409 26 120 208 340 100
Total: 1610 = 23 x 7 x 5 x 2
63.5Run the number of digit appearances together to form a 14 digit number: 22177741143313 = 7 x 29 x 31 x 443 x 1867 x 4261.
Methods 63.3 and 63.4 produce no features when applied to the letters. This is to be expected since the digit appearances was originally developed from the word sums, and not from the letters.
63.6Only digit 1 and 6 appear a multiple of 11 times. 1 + 6 = 7.
64.God is the beginning and the end. This gives two principles which can be applied to the structure of the passage. The first is the Name, which represents God. Its numeric sum is 26. This can be applied to the beginning of each word in the passage. For each of the 33 words in the passage, beginning with the first letter of each word, extract 25 more letters (for a total of 26). The result is presented in this table.
64.1.1The very first column on the left would be the first letter of each word. As seen before, the sum total of the first letters is divisible by 7 (see Applying Revelation 1:8 To Exodus 34:6b-7, The Beginning and the End
, Feature 7.2).
64.1.2The next column would be the second letter of each word. As each instant in time is a new beginning
, we could expect this column's sum to be divisible by 7 as well. And it is (see I Am
, Feature 2.3).
64.1.3Since the shortest word in the passage consists of two letters, the third column sometimes has to borrow
a letter from the next word. Thus we do not expect the sum of the third column to be divisible by 7. And it is not.
64.2Taking note of the column totals that are divisible by 7 we find...
Column Sum 1 1330 = 7 x 19 x 5 x 2 (first letter of each word) 2 1743 = 7 x 3 x 83 (second letter of each word) 5 1295 = 7 * 5 * 37 (fifth letter of each word) 7 2415 = 7 * 5 * 3 * 23 (seventh of each word) 16 1617 = 7 * 7 * 11 * 3 (sixteenth of each word) 21 2275 = 7 * 5 * 5 * 13 (twenty-first of each word)
The six columns listed immediately above have sums divisible by 7. Out of 26 random sums, chance would say only 3, or at most 4 sums would be divisible by 7. Six sums beat the odds.
64.3.1The sum of the six columns (col #): 1 2 5 7 16 21 would be 52 (13 x 4). The total of their "sums": 10675 = 7 * 5 * 5 * 61. This is nothing special since each individual column is already divisible by 7. However, the sum of the factors is 78, and 78 factors into 13 x 3 x 2.
64.3.2Since we are using YHWH progressively through the words of the proclamation, we can apply the six column numbers as a pattern progressively through the words by counting.
Column number: 1 2 5 7 16 21 Count: 1 3 8 15 31 52 Adjusted word position: 1 3 8 15 31 19 Word found: 317 26 131 351 680 161
Total of words found: 1666 (2 x 7 x 7 x 17).
64.4.1Eight rows out of 33 are divisible by 7 (rows 6 13 14 20 23 25 27 31) when we would normally expect only 4 or 5.
64.4.2Unlike feature 64.3 above, the row numbers produce no results when applied to the words by counting.
Row #: 6 13 14 20 23 25 27 31 Direct: 120 72 191 31 126 100 106 680 Count: 6 19 33 20 10 2 29 27 Found: 120 161 322 31 72 26 102 106
Direct total: 1426 (no feature). Found total: 940 (no feature).
A slight adjustment has to be made because rows are not columns. Normally, the count through the words begins with the first item in the pattern (row 6). However, if we shift the pattern over seven positions, the result is divisible by 7. (N.B. Shifting 1, 2, 3 ... or 6 times yields no result for the words. Only a shift of 7 works.)
Original pattern: 6 13 14 20 23 25 27 31 Shifted 7 positions: 7 13 26 40 60 83 108 135 166 Adjusted position: 7 13 26 7 27 17 9 3 1 Word found: 221 72 102 221 106 456 208 26 317
Total: 1729 (7 x 13 x 19 SF: 39 = 3 x 13).
64.4.3The sum total of these eight rows: 11123 = 7 x 7 x 227. Unlike the columns, an extra factor of 7 appears immediately.
65.Record the first and last letter positions of each word in two lists. Since there are 33 words, gather them into groups of threes for a total of eleven groups per list. For each group of three, run the digits together forming larger numbers. The result is the list below.
(E.g. First letter positions of the first three words are 1, 6 and 10. These three numbers are then run together forming a larger number: 1610. Continue for the next set of three words.)
First positions Last positions
1610 5913
141620 151924
252832 273134
353842 374144
454854 475356
576064 596368
697375 727478
798285 818488
899195 909497
98101105 100104106
107112115 111114119
_________ _________
Total: 209388897 215550527
65.1The grand total is 424939424. The result is a number that reads exactly the same from right to left or right to left. God is the same from beginning to end, and even in the present. It may not appear that God is at work, but He is always there.
65.2The factors of this nine digit number are also nine in number (2 x 2 x 2 x 2 x 2 x 7 x 13 x 73 x 1999). The factors of 7 and 13 confirm God’s handiwork. Add the nine factors: 2102 = 2 x 1051 (SF: 1053 = 3 x 3 x 3 x 3 x 13 SF: 25 = 5 x 5 SF: 10 = 2 x 5 SF: 7.)
65.3The factors of 424939424 can be used directly as word positions:
Factor: 2 2 2 2 2 7 13 73 1999 Letter: 26 26 26 26 26 221 72 221 161
Total: 805 (5 x 7 x 23 SF: 35 = 5 x 7 SF: 12 = 2 x 2 x 3 SF: 7).
65.4The factors of 424939424 can be multiplied step by step and used as word positions:
Factors: 2 2 2 2 2 7 13 73 1999 Multiplied: 2 4 8 16 32 224 2912 212576 424939424 Direct word position: 2 4 8 16 32 26 8 23 8 Word Found: 26 31 131 126 106 102 131 126 131
Total of the words found: 910 (2 x 5 x 7 x 13).
65.5Since there are 33 words in the proclamation (3 x 11), groups of eleven could also be tried. Take the positions of the first letter of the first eleven words and run them together into one large number. Do the same with the next set of eleven, and then the remaining eleven. Create a second list for the last letters of the words.
First Positions 16101416202528323538 4245485457606469737579 +828589919598101105107112115 ___________________________ 828594181184974914105173232 a) Last Positions 59131519242731343741 4447535659636872747881 +8488909497100104106111114119 ____________________________ 8488914003767282985715205741 b)
The total for a) factors: 24 x 33 x 7 x 13 x 47 x 448455011942092779913. The total for b) factors: 13 x 652993384905175614285785057. The sum of a) + b): 9317508184952257899820378973 = 13 x 716731398842481376909259921.
The sum of a) and b) is not a symmetrical number, but the constant appearance of the factor 13 still points to God.
66.1Seven word sums are prime numbers (a 1 in 7 coincidence):
1 4 8 14 18 20 24 317 31 131 191 29 31 409 (The positions and word sums do not yield any features.)
66.1.1These 7 words have a total of 28 (7 x 4) letters.
66.1.2The positions of the letters in these seven words:
1 2 3 4 5 14 15 28 29 30 31 48 49 50 51 52 53 64 65 66 67 68 73 74 85 86 87 88
The sum of the positions: 1288 = 2 x 2 x 2 x 7 x 23.
66.2This means 26 words are not prime numbers, and point to God’s name.
66.2.1Three words are not prime numbers and in positions divisible by 7:
7 21 28 221 165 62
Total of the positions: 56 = 23 x 7. SF: 13. The sum of the factors is the new feature.
Total of the words: 448 = 26 x 7.
66.2.2Four words are not prime numbers and are multiples of 7:
16 19 23 33 126 161 126 322
Total of the positions: 91 = 7 x 13.
Total of the words: 735 = 3 x 5 x 72. The sum of the words produces an extra 7.
67.1Round each word down to one significant digit (317 becomes 300, and 29 becomes 20): 300 20 20 30 200 100 200 100 200 70 400 300 70 100 300 100 400 20 100 30 100 100 100 400 100 100 100 60 100 100 600 100 300. The sum of these numbers is 5320 (2 x 2 x 2 x 5 x 7 x 19).
67.2Following the rules of math and rounding to one significant digit: 300 30 30 30 200 100 200 100 200 70 400 300 70 200 400 100 400 30 200 30 200 200 100 400 100 100 100 60 100 100 700 100 300. Total: 5950 = 2 x 5 x 5 x 7 x 17
67.3Round every number up to one significant figure unless it is a round number: 400 30 30 40 300 200 300 200 300 80 500 400 80 200 400 200 500 30 200 40 200 200 200 500 100 200 200 70 200 100 700 200 400. Total: 7700 (2 x 2 x 5 x 5 x 7 x 11).
68.Seventy is the only letter in the passage divisible by 7. The following words have the letter 70.
Word position: 16 17 23 25 27 30 32 33 Word sum: 126 456 126 100 106 100 106 322
68.1.1The sum of the word positions: 203 (7 x 29).
68.1.2The sum of the words: 1442 (2 x 7 x 103 SF:112 = 7 x 2 x 2 x 2 x 2).
68.2.1Four times, the letter 70 appears as the first letter of the word, in letter positions: 57, 82, 89, and 105. The sum of these positions is 333. This is not divisible by 7 or 13, but this number perfectly illustrates the one God who is, was, and is to come, from beginning to end, first and last.
68.2.2Only one time does the letter 70 appear at the end of a word. Its letter position is 63 (7 x 3 x 3, SF:13).
68.3.1Take the first word position from the list and every other afterwards: 16 23 27 32. The sum is 98 = 2 x 7 x 7.
68.3.2Take the second word position of the list, and every other afterwards: 17 25 30 33. The sum is 105 = 3 x 5 x 7.
68.4From the list of eight words, pair them up first to last, second to second last and so on.
68.4.1.1The positions for the first and last: 16 + 33 = 49 (7 x 7). Coincidentally, their sums are both divisible by seven.
68.4.1.2And of course if their sums were added, the result would also be divisible by 7.
68.4.2The second pair: 17 + 32 = 49 (again!).
68.4.3The third pair yields no feature, but remaining two in the middle do. 25 + 27 = 52 (2 x 2 x 13).
68.5.2Coincidentally, the fifteenth word's last letter rests in position 56. This means the sum of the letter positions, from the first word, to the end of the fifteenth word is also divisible by 7: 1596 (2 x 2 x 3 x 7 x 19). The remainder of the letter positions from 57 to 119 would again be divisible by 7: 5544 (2 x 2 x 2 x 3 x 3 x 7 x 11).
69.Revelation 1:8 describes God as being the same whether He is at the beginning or end, first or last, Alpha or Omega. This paired nature appears in the digits of the word sums. Eight words have repeating digits in their sums:
Position: 7 8 11 14 19 25 30 33 Word sum: 221 131 447 191 161 100 100 322
69.1Sum of the positions: 147 = 3 x 7 x 7.
69.2Sum of the words: 1673 = 7 x 239.
69.3A smaller list exists within the one above. Select only the word sums where the digits are next to each other:
7 11 25 30 33 221 447 100 100 322
The sum of these five words: 1190 (17 x 7 x 5 x 2).
70.1Take the third, 13th, 23rd, and 33rd words:
Position: 3 13 23 33 Word: 26 72 126 322
The total is: 546 = 2 x 3 x 7 x 13
70.2This also works with the letters. Taking the third and every tenth letter after:
Position: 3 13 23 33 43 53 63 73 83 93 103 113 Letter: 100 5 6 200 90 40 70 30 6 10 10 70
Total of letters: 637 = 7 x 7 x 13.
70.3.1Since the same method yields sums divisible by 7 and 13 both in words and letters, this leads to combining the totals in 70.1 and 70.2. 546 + 637 = 1183 (7 x 13 x 13). An extra factor of 13 points to God’s name.
70.3.2Even the first and last items of both lists can be combined: 26 + 322 + 100 + 70 = 518 (2 x 7 x 37).
70.3.3Take every odd positioned item from each list:
Position: 3 23 Position: 3 23 43 63 83 103 Word: 26 126 Letter: 100 6 90 70 6 10
The sum of the words and letters is a symmetrical number whose first or last digits with the middle digit is divisible by seven: 434 = 2 x 7 x 31.
71.1Take each word sum and divide it by the value of the Name (26): 12 1 1 1 9 4 8 5 8 2 17 13 2 7 13 4 17 1 6 1 6 7 4 15 3 3 4 2 3 3 26 4 12. The total of the results: 224 (2 x 2 x 2 x 2 x 2 x 7).
71.2Each word sum divided by 13 (a factor of God’s Name): 24 2 2 2 19 9 17 10 16 5 34 26 5 14 27 9 35 2 12 2 12 14 9 31 7 7 8 4 7 7 52 8 24. Total: 462 (2 x 3 x 7 x 11).
72.Words with letters greater or equal to 100.
a) Word position b) Word sum c) Position of letter d) Letter value a) 1 1 5 7 9 11 12 15 17 19 21 22 24 31 31 33 b) 317 317 254 221 208 447 340 351 456 161 165 184 409 680 680 322 c) 3 4 16 26 33 41 44 55 62 71 77 80 88 107 109 115 d) 100 200 200 200 200 400 200 300 300 100 100 100 400 300 300 200
72.1.1The sum of line a) 259 = 7 x 37.
72.1.2The sum of line b) 5512 = 2 x 2 x 2 x 13 x 53.
72.1.3The sum of line c) 931 = 7 x 7 x 19. (Only line d) has no features.)
72.1.4Six of the letters have positions with double digits:
33 44 55 77 88 115 200 200 300 100 400 200
Letter total: 1400 (2 x 2 x 2 x 5 x 5 x 7).
72.1.5Three of the letters are in word positions with double digits. The sum of the letters: 700 = 2 x 2 x 5 x 5 x 7 (SF: 21 = 3 x 7 SF: 10 = 2 x 5 SF: 7).
72.2There are even results in the letters less than 100.
a) 1 1 1 2 2 2 2 3 3 3 3 4 4 5 5 5 6 b) 317 317 317 26 26 26 26 26 26 26 26 31 31 254 254 254 120 c) 1 2 5 6 7 8 9 10 11 12 13 14 15 17 18 19 20 d) 6 10 1 10 5 6 5 10 5 6 5 1 30 8 6 40 6 a) 6 6 6 6 7 7 8 8 8 8 9 9 10 10 10 b) 120 120 120 120 221 221 131 131 131 131 208 208 72 72 72 c) 21 22 23 24 25 27 28 29 30 31 32 34 35 36 37 d) 8 50 6 50 1 20 1 80 10 40 6 2 8 60 4 a) 11 11 11 12 12 13 13 13 14 14 14 14 14 14 15 b) 447 447 447 340 340 72 72 72 191 191 191 191 191 191 351 c) 38 39 40 42 43 45 46 47 48 49 50 51 52 53 54 d) 6 1 40 50 90 8 60 4 30 1 30 80 10 40 50 a) 15 16 16 16 17 17 17 18 18 18 18 18 19 19 19 20 b) 351 126 126 126 456 456 456 29 29 29 29 29 161 161 161 31 c) 56 57 58 59 60 61 63 64 65 66 67 68 69 70 72 73 d) 1 70 6 50 6 80 70 6 8 9 1 5 6 50 5 30 a) 20 21 21 21 22 22 23 23 23 24 24 24 25 25 26 b) 31 165 165 165 184 184 126 126 126 409 409 409 100 100 102 c) 74 75 76 78 79 81 82 83 84 85 86 87 89 90 91 d) 1 10 50 5 80 4 70 6 50 1 2 6 70 30 2 a) 26 26 26 27 27 27 28 28 28 29 29 29 29 30 30 b) 102 102 102 106 106 106 62 62 62 102 102 102 102 100 100 c) 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 d) 50 10 40 6 70 30 2 50 10 2 50 10 40 70 30 a) 31 31 31 32 32 32 33 33 33 33 b) 680 680 680 106 106 106 322 322 322 322 c) 108 110 111 112 113 114 116 117 118 119 d) 30 10 40 6 70 30 2 70 10 40
72.2.1The sum of line a): 1730.
72.2.2The sum of line b): 18536 = 2 x 2 x 2 x 7 x 331.
72.2.3The sum of line c): 6209 = 7 x 887.
72.2.4The sum of line d): 2574 = 2 x 3 x 3 x 11 x 13.
72.2.5Letters in word positions with double digits: 442 = 2 x 13 x 17.
73.Our present number system is base 10. We count from 1 to 9 before adding an extra digit. From 10 we count to 99 and carry to the next place. This structure exists in the Exodus verse even though the ancient Hebrews did not have a base ten numbering system exactly like ours, and did not have Arabic numerals.
73.1.1The sum of letters from positions 1 to 9: 343 = 7 x 7 x 7. (God’s perfect number shows 3 times!)
73.1.2The sum of letters from positions 10 to 99: 4511 = 13 x 347 (The number of the Divine Name appears next.)
73.1.3The sum of letters from positions 100 to 119: 1320 = 2 x 2 x 2 x 3 x 5 x 11 (We are assured He is first and last with the number 11. The three 2s follow Revelation 1:8 Alpha and Omega
, Beginning and End
, and First and Last
. The lone 3 matches is, was and is to come
.)
73.2343 shows the uniqueness of the single digit letter positions, and this sets the first part of the verse apart. The rest of the verse also shows God’s perfect number 3 times. The sum of the letters from 10 to 119 is 5831 (7 x 7 x 7 x 17 [every factor has the digit 7]).
Features 73.1 and 73.2 could be explained a different way. In Revelation 1:8, the unchanging God says He is Alpha and Omega
. He is beginning and end, or first and last, but He remains the same. The easiest way to illustrate Alpha and Omega being different, and yet the same, is in a circle. Any point on the circle marks a beginning and end. Exodus 34:6-7 can be laid out as a circle with the last letter next to the first. The dividing point for beginning and end is between the two divine names. This is the only part in the passage where two consecutive words are the same.
As seen before, from the actual beginning of the passage, to the end of the first divine name, the sum is 343. And from the beginning of the second divine name, to the end of the passage, the sum is 5831.
343 = 7 x 7 x 7 5831 = 17 x 7 x 7 x 7
343 is exactly one eighteenth of the entire passage.
The above pattern is very basic and quite obvious, but there are other structures in the positions of the letters.
73.3All letter positions with the digit 7.
a) Position b) Letter a) 7 17 27 37 47 57 67 70 71 72 73 74 75 76 77 78 79 87 97 107 117 b) 5 8 20 4 4 70 1 50 100 5 30 1 10 50 100 5 80 6 30 300 70
Total of letters: 949 (13 x 73).
73.4The ancients did not have the number zero
, but this special number also has its place in Exodus.
All letter positions containing the digit 0.
a) Position b) Letter a) 10 20 30 40 50 60 70 80 90 100 101 102 103 104 105 106 107 108 b) 10 6 10 40 30 6 50 100 30 10 2 50 10 40 70 30 300 30 a) 109 110 b) 300 10
Total of letters: 1134 (2 x 3 x 3 x 3 x 3 x 7 SF:21 = 7 x 3).
73.5.1Two other numbers match the feature above.
All letter positions containing the digit 5.
a) Position b) Letter a) 5 15 25 35 45 50 51 52 53 54 55 56 57 58 59 65 75 85 95 105 115 b) 1 30 1 8 8 30 80 10 40 50 300 1 70 6 50 8 10 1 6 70 200
Total of letters: 980 (2 x 2 x 5 x 7 x 7)
73.5.2All letter positions containing the digit 6.
a) Position b) Letter 6 16 26 36 46 56 60 61 62 63 64 65 66 67 68 69 76 86 96 106 116 10 200 200 60 60 1 6 80 300 70 6 8 9 1 5 6 50 2 70 30 2
Total of letters: 1176 (2 x 2 x 2 x 3 x 7 x 7)
Features 73.4 & 73.5 (immediately above) cover three of the four digits in the Divine Name (10-5-6-5). Only the digit 1 produces no feature.
The odds would seem to indicate that out of the ten digits (0-9), at most one or two of them would have produced a sum divisible by 7. The Exodus verse produced four.
73.6The number 11 is the first (and smallest) number with two identical digits. As stated before, this can be a mathematical representation of the one God from beginning to end.
All letter positions containing the digits 11.
11 110 111 112 113 114 115 116 117 118 119 5 10 40 6 70 30 200 2 70 10 40
Total of letters: 483 (3 x 7 x 23 SF:33 the number of words and 11 x 3)
73.7The number 13 is related to YHWH.
All letter positions containing the digits 13.
13 113 5 70
Total of positions: 126 (2 x 3 x 3 x 7). Total of letters: 75
In this case, the sum of the letters produce no features. However, the sum of the positions does.
73.8All Letter values with the digit 1.
2 3 5 6 10 14 25 28 30 39 49 52 56 67 71 74 75 77 80 85 93 10 100 1 10 10 1 1 1 10 1 1 10 1 1 100 1 10 100 100 1 10 100 103 110 118 10 10 10 10
73.8.1Total of letters: 520 = 2 x 2 x 2 x 5 x 13
73.8.2Total of positions: 1372 = 2 x 2 x 7 x 7 x 7
All Letter values with the digit(s) 2.
4 16 26 27 33 34 44 86 91 98 101 115 116 200 200 200 20 200 2 200 2 2 2 2 200 2
73.8.3Total of letters: 1232 = 2 x 2 x 2 x 2 x 7 x 11
73.8.4Total of positions: 791 = 7 x 113
All Letter values with the digit(s) 3.
15 48 50 55 62 73 90 97 106 107 108 109 114 30 30 30 300 300 30 30 30 30 300 30 300 30
73.8.5Total of letters: 1470 = 2 x 3 x 5 x 7 x 7
73.8.6Total of positions: 1034 = 2 x 11 x 47
All Letter values with the digit(s) 7.
57 63 82 89 96 105 113 117 70 70 70 70 70 70 70 70
Total of positions: 722 = 2 x 19 x 19
73.8.7Total of letters: 560 = 2 x 2 x 2 x 2 x 5 x 7 (This one naturally is divisible by 7).
Again four out of ten digits yield features. Of these four, the digit 1 also yielded a digit of 13. Previously, with the letter positions, the digit 1 produced no feature. With the letters, it does. If the digit 1 stands for the one God, wouldn't He have made the numbers Numerics Gematria show up in both cases? Perhaps God wanted to make a distinction. The positions are simply that, a place along a number line. The letters actually form words and words have meaning. It is the words that give us the proclamation, not the positions.
Two other digits yield features of 13 (a factor of the Tetragrammaton), but not features of 7.
All Letter values with the digit(s) 5.
7 9 11 13 22 24 42 54 59 68 70 72 76 78 84 92 99 102 5 5 5 5 50 50 50 50 50 5 50 5 50 5 50 50 50 50
Total of positions: 982 = 2 x 491
73.8.8Total of letters: 585 = 3 x 3 x 5 x 13
All Letter values with the digit(s) 8.
17 21 29 35 45 51 61 65 79 8 8 80 8 8 80 80 8 80
73.8.9Total of positions: 403 = 13 x 31
Total of letters: 360 = 2 x 2 x 2 x 3 x 3 x 5
Interestingly, (these digits together) 5 + 8 = 13.
74.1The 28th word (1 in 7) is unique in that it's word position, word sum, letter positions and letter values, can all be turned upside down and still be read as actual numbers:
Original Each digit
individually With positions
flipped reversed
Word position: 28 28 82
Word sum: 62 92 29
Letter position: 98 99 100 68 66 100 86 66 001
Letter value: 2 50 10 2 50 10 2 05 01
74.2These 19 word sums can also be turned upside down: 26 26 120 221 208 191 126 29 161 165 126 100 102 106 62 102 100 680 106.
Upside down, their sums would be: 92 92 021 122 802 161 921 62 191 591 921 001 201 901 29 201 001 089 901 = 6300 = 2 x 2 x 3 x 3 x 5 x 5 x 7.
74.3All the word sums can be turned upside down if the digits 3, 4 and 7 are simply dropped. This produces a new list: 1 92 92 1 52 021 122 11 802 2 2 161 15 921 95 62 191 1 591 81 921 60 001 201 901 29 201 001 089 901 22. The resulting total is 6643 (7 x 13 x 73). (NB The digits 3, 4 and 7 together total 14 [7 x 2]. Note also how 3, 4 and 7 are similar to the actual reference to the proclamation.)
74.4Only the 11th and 12th words become unrecognizable as numbers when they are flipped upside down, and disappear. The sum of these two words is 787 (a symmetrical number pointing the same perfect God first and last). These two words have 7 letters occupying letter positions: 38 39 40 41 42 43 and 44. The sum of these positions is: 287 = 41 x 7.
75.Words and letters are the scaffolding of the passage. The number of letters in each word point inside the passage to other features. Revelation 1:8 tells us how it is put together.
List of letters per word 5 4 4 2 4 5 3 4 3 3 4 3 3 6 3 3 4 5 4 2 4 3 3 4 2 4 3 3 4 2 5 3 5
75.1Revelation 1:8 mentions three pairs of characteristics for God. To apply this to the list above, we pair up the numbers. Since the list has 33 numbers, pairing them up would leave 5
all by itself at the end. In order to pair it with another number, we double the list first.
List of letters doubled 5 4 4 2 4 5 3 4 3 3 4 3 3 6 3 3 4 5 4 2 4 3 3 4 2 4 3 3 4 2 5 3 5 5 4 4 2 4 5 3 4 3 3 4 3 3 6 3 3 4 5 4 2 4 3 3 4 2 4 3 3 4 2 5 3 5
Numbers are grouped in pairs and used directly as word positions.
a) paired number b) word position c) word found a) 54 42 45 34 33 43 36 33 45 42 43 34 24 33 42 b) 21 9 12 1 33 10 3 33 12 9 10 1 24 33 9 c) 165 208 340 317 322 72 26 322 340 208 72 317 409 322 208 a) 53 55 44 24 53 43 34 33 63 34 54 24 33 42 43 b) 20 22 11 24 20 10 1 33 30 1 21 24 33 9 10 c) 31 184 447 409 31 72 317 322 100 317 165 409 322 208 72 a) 34 25 35 b) 1 25 2 c) 317 100 26
Total: 7497 = 3 x 3 x 7 x 7 x 17.
75.2The same paired numbers can also be used directly as letter positions.
a) paired number b) letter found a) 54 42 45 34 33 43 36 33 45 42 43 34 24 33 42 53 55 44 b) 50 50 8 2 200 90 60 200 8 50 90 2 50 200 50 40 300 200 a) 24 53 43 34 33 63 34 54 24 33 42 43 34 25 35 b) 50 40 90 2 200 70 2 50 50 200 50 90 2 1 8
Total of the letters: 2555 = 5 x 7 x 73.
75.3Revelation 1:8 also states that God is, was, and is to come.
This is a single characteristic composed of three parts. This can also be applied to the list in 74 above. Gather the numbers into groups of three. (Since there are 33 numbers, they form eleven complete groups of three.)
List grouped in threes 544 245 343 343 363 345 424 334 243 342 535
These new numbers are used directly as word positions:
Triplets direct as word positions a) 544 245 343 343 363 345 424 334 243 342 535 b) 16 14 13 13 33 15 28 4 12 12 7 c) 126 191 72 72 322 351 62 31 340 340 221
Total: 2128 = 2 x 2 x 2 x 2 x 7 x 19.
76.The basic structure of Exodus 34:6b-7 points out other numeric features. The verse has 33 words (11 x 3), 119 letters (17 x 7), a sum of 6174 (7 x 7 x 7 x 3 x 3 x 2). This produces a list of factors: 11 3 17 7 7 7 7 3 3 2.
Factor: 2 3 7 11 17 Appearances: 1 3 4 1 1
76.1Using the individual factors only once as positions:
Position: 2 3 7 11 17 Word: 26 26 221 447 456 Letter: 10 100 5 5 8
76.1.1Total of the words: 1176 = 7 x 7 x 3 x 2 x 2 x 2.
76.1.2Total of the letters: 128 = 2 x 2 x 2 x 2 x 2 x 2 x 2 (Seven 2s.)
76.1.3The entire list of factors applied as letter positions.
Factor as position: 11 3 17 7 7 7 7 3 3 2 Letter found: 5 100 8 5 5 5 5 100 100 10
Total of letters found: 343 = 7 x 7 x 7
76.1.4Counting through the letters with the list of factors.
Factor: 11 3 17 7 7 7 7 3 3 2 Count: 11 14 31 38 45 52 59 62 65 67 Letter: 5 1 40 6 8 10 50 300 8 1
Total of letters found: 429 = 3 x 11 x 13
76.2From the list of factors in 76.1, we can apply the principle from Revelation 1:8 of is, was and is to come
. Use each factor as a word position and note the words that came before and after it.
2: 317 26 26 = 369 = 41 x 3 3: 31 26 26 = 83 is a prime 7: 120 221 131 = 472 = 2 x 2 x 2 x 59 SF:65 = 13 x 5 11: 72 447 340 = 859 is a prime number. 17: 126 456 29 = 611 = 13 x 47
Total: 2394 = 7 x 2 x 3 x 3 x 19.
76.3.1The feature above used each factor only one time, while the list actually has multiple appearances of each factor. All the factors can be used as word positions, and then following Revelation 1:8, the word positions before and after are also included.
Factors Used As Word Positions (With positions before & after) 10 11 12 2 3 4 16 17 18 6 7 8 6 7 72 447 340 26 26 31 126 456 29 120 221 131 120 221 8 6 7 8 6 7 8 2 3 4 2 3 4 1 2 3 131 120 221 131 120 221 131 26 26 31 26 26 31 317 26 26
Word total: 3976 = 2 x 2 x 2 x 7 x 71.
76.3.2It also works as letter positions:
Factors Used As Letter Positions (With positions before & after) 10 11 12 2 3 4 16 17 18 6 7 8 6 7 8 10 5 6 10 100 200 200 8 6 10 5 6 10 5 6 6 7 8 6 7 8 2 3 4 2 3 4 1 2 3 10 5 6 10 5 6 10 100 200 10 100 200 6 10 100
Total of letters found: 1365 = 3 x 5 x 7 x 13 SF: 28 = 2 x 2 x 7 SF: 11.
76.4We began this section looking at the factors from the number of words, the number of letters, and the passage’s numeric sum. Now we look at each separately.
The passage has 119 letters (17 x 7).
76.4.1.1Divide the passage into seven sections, each with 17 letters. Note the position and letter at the beginning and end of each section.
Position: 1-17 18-34 35-51 52-68 69-85 86-102 103-119 Letter: 6 8 6 2 8 80 10 5 6 1 2 50 10 40
The total of the letters: 234 = 2 x 3 x 3 x 13.
In this case the sum of the positions is mathematically fixed to be divisible by 7: 840 (2 x 2 x 2 x 3 x 5 x 7). The sum of the factors, however, coincidentally go further: 21 = 3 x 7 (SF: 10 = 5 x 2. SF: 7.)
76.4.1.2The last letters of each section:
Letter position: 18 35 52 69 86 103 Letter: 6 8 10 6 2 10
Total: 42 = 2 x 3 x 7 (SF: 12 = 2 x 2 x 3 SF: 7).
76.4.1.2From the list in 76.4.1.1, take only those that are also the first letter of a word.
Letter position: 1 35 69 85 Letter: 6 8 6 1
Total: 21 = 3 x 7.
76.4.2.1Divide the passage into seventeen sections of 7 letters each, and list the first and last of each section.
a) letter position b) letter a) 1 7 8 14 15 21 22 28 29 35 36 42 43 49 50 56 57 63 64 b) 6 5 6 1 30 8 50 1 80 8 60 50 90 1 30 1 70 70 6 a) 70 71 77 78 84 85 91 92 98 99 105 106 112 113 119 b) 50 100 100 5 50 1 2 50 2 50 70 30 6 70 40
Total of line b): 1199 = 11 x 109. (The same God beginning and end.)
76.4.2.2List the last letter of each section:
a) letter position b) letter a) 8 15 22 29 36 43 50 57 64 71 78 85 92 99 106 113 b) 6 30 50 80 60 90 30 70 6 100 5 1 50 50 30 70
Total of line b): 728 = 2 x 2 x 2 x 7 x 13.
76.4.2.3The factors for the total number of letters in the passage (7 and 17) can be used several other ways along with the factors for the total number of words (3 and 11). Start with the 7th word and collect every seventh word after. Along with each word, also take the third word before and after it.
a) 3rd word before b) 7th word c) 3rd word after
a) b) c) a) b) c) a) b) c) a) b) c)
Position: 4 7 10 11 14 17 18 21 24 25 28 31
Word: 31 221 72 447 191 456 29 165 409 100 62 680
Sum of the words: 2863 = 7 x 409 (SF: 416 = 25 x 13).
76.4.2.4Starting with the first word, take every 17th word after. (There will only be two.) Also take every third word before and after the first and 17th.
a) 3rd word before b) 17th word c) 3rd word after a) b) c) a) b) c) Position: 31 1 4 15 18 21 Word: 680 317 31 351 29 165
Sum of the words: 1573 = 11 x 11 x 13 (SF: 35 = 5 x 7 SF: 12 = 2 x 2 x 3 SF: 7).
76.4.2.5Begin with the first word, and take every seventh after. With each word, take the eleventh word before and after it.
a) 3rd word before b) 17th word c) 3rd word after a) b) c) a) b) c) a) b) c) a) b) c) a) b) c) Position: 23 1 12 30 8 19 4 15 26 11 22 33 18 29 7 Word: 126 317 340 100 131 161 31 351 102 447 184 322 29 102 221
Total: 2964 = 2 x 2 x 3 x 13 x 19 (SF: 39 = 3 x 13).
76.4.2.6This is almost like the previous feature, but instead of beginning with the first word, start with the seventh word, and take every seventh after. Then take every eleventh word before and after each of them.
a) 3rd word before b) 17th word c) 3rd word after a) b) c) a) b) c) a) b) c) a) b) c) Position: 29 7 18 3 14 25 10 21 32 17 28 6 Word: 102 221 29 26 191 100 72 165 106 456 62 120
Total: 1650 = 2 x 3 x 5 x 5 x 11 (SF: 26 = 2 x 13).
76.4.3.1We return to the technique in 76.4.1.2 and explore another avenue. Gather all the letters that are in positions divisible by 13 and that are also the first or last letter of a word.
First/Last: L L F L Position: 13 78 91 104 Letter: 5 5 2 40
The sum of the letters: 52 (13 x 2 x 2). Note how the only one that is first in a word is in position 91 (7 x 13).
76.4.3.276.4.3.1 counted every 13th letter. The search began with the 13th letter. It could also have started with the first letter (i.e. God being first) and taken every 13th after. The results are then filtered by taking only those positions that are at the beginning or end (God also the beginning and end) of a word.
F F L L F F Position: 1 14 27 53 79 105 Letters: 6 1 20 40 80 70
The sum of the letters: 217 = 7 x 31 (SF: 38 = 2 x 19 SF: 21 = 3 x 7 SF: 10 = 2 x 5 SF: 7).
76.4.3.3Starting with the first word, and every 13th after, take the third word before and after it.
a) 3rd word before b) 17th word c) 3rd word after a) b) c) a) b) c) a) b) c) Position: 31 1 4 11 14 17 24 27 30 Word: 680 317 31 447 191 456 409 106 100
Total: 2737 = 7 x 17 x 23.
76.4.3.4Take every 13th letter along with the third letter before and after it.
a) 3rd word before b) 17th word c) 3rd word after a) b) c) a) b) c) a) b) c) a) b) c) a) b) c) Position: 10 13 16 23 26 29 36 39 42 49 52 55 62 65 68 Letter: 10 5 200 6 200 80 60 1 50 1 10 300 300 8 5 Position: 75 78 81 88 91 94 101 104 107 114 117 1 Letter: 10 5 4 400 2 40 2 40 300 30 70 6
Total: 2145 = 3 x 5 x 11 x 13.
76.4.3.5Beginning with the first letter of the passage, add up every 13th letter along with the seventh letter before and after it.
a) 3rd word before b) 17th word c) 3rd word after a) b)c) a)b) c) a) b) c) a) b) c) a) b) c) Position: 113 1 8 7 14 21 20 27 34 33 40 47 46 53 60 Letter: 70 6 6 5 1 8 6 20 2 200 40 4 60 40 6 Position: 59 66 73 72 79 86 85 92 99 98 105 112 111 118 6 Letter: 50 9 30 5 80 2 1 50 50 2 70 6 40 10 10
Total: 889 = 7 x 127.
76.4.3.6Add up every 13th letter along with the seventh letter before and after it.
a) 3rd word before b) 17th word c) 3rd word after a) b) c) a) b) c) a) b) c) a) b) c) a) b) c) Position: 6 13 20 19 26 33 32 39 46 45 52 59 58 65 72 Letter: 10 5 6 40 200 200 6 1 60 8 10 50 6 8 5 Position: 71 78 85 84 91 98 97 104 111 110 117 5 Letter: 100 5 1 50 2 2 30 40 40 10 70 1
Total: 966 = 2 x 3 x 7 x 23 (SF: 35 = 5 x 7 SF: 12 = 2 x 2 x 3 SF: 7).
76.5The passage has 33 (11 x 3) words.
76.5.1For every 11th word, include the words before and after each one:
10 11 12 21 22 23 32 33 1 72 447 340 165 184 126 106 322 317
Total: 2079 = 3 x 3 x 3 x 7 x 11.
76.5.2If we applied the same technique to every 3rd word, this would simply be the sum of the entire passage: 6174 (and automatically be divisible by three 7s).
76.6What other values might work like the factors from the structure of the passage? The easiest to check is the value of the Tetragrammaton (26).
76.6.1The 26th word of the proclamation has a value of 102. Note the words before and after it.
Word: 25 26 27 Sum: 100 102 106
Total: 308 = 2 x 2 x 7 x 11
76.6.2Using the letters of the Tetragrammaton,
note every 10th Word, and those before and after it:
Word: 9 10 11 19 20 21 29 30 31 Sum: 208 72 447 161 31 165 102 100 680 Total: 1966 = 2 x 983
note every 5th Word, and those before and after:
Word: 4 5 6 9 10 11 14 15 16 19 20 21 24 25 26 Sum: 31 254 120 208 72 447 191 351 126 161 31 165 409 100 102 Word: 29 30 31 Sum: 102 100 680 = 3650
note every 6th Word along with its neighbours:
Word: 5 6 7 11 12 13 17 18 19 23 24 25 29 30 31 Sum: 254 120 221 447 340 72 456 29 161 126 409 100 102 100 680 Total: 3617
It would seem as if YHWH did not produce any features. But this is if each total was taken by itself. If they are taken together, we find something different.
All three sums together: 1966 + 3650 + 3617 = 9233 = 7 x 1319 (SF:1326 = 2 x 3 x 13 x 17 SF:35 = 5 x 7 SF:12 = 2 x 2 x 3 SF:7) Adding in the sum from every 5th word
a second time: 9233 + 3650 = 12883 = 13 x 991.
76.6.3Applying the letters of YHWH to the letters of the passage...
Note every 10th Letter with the one before and after:
10: 5 10 5 = 20
20: 40 6 8 = 54
30: 80 10 40 = 130
40: 1 40 400 = 441
50: 1 30 80 = 111
60: 50 6 80 = 136
70: 6 50 100 = 156
80: 80 100 4 = 184
90: 70 30 2 = 102
100: 50 10 2 = 62
110: 300 10 40 = 350
Total: 1746
Count every 5th Letter along with its predecessor and successor:
5: 200 1 10 = 211
10: 5 10 5 = 20
15: 1 30 200 = 231
20: 40 6 8 = 54
25: 50 1 200 = 251
30: 80 10 40 = 130
35: 2 8 60 = 70
40: 1 40 400 = 441
45: 200 8 60 = 268
50: 1 30 80 = 111
55: 50 300 1 = 351
60: 50 6 80 = 136
65: 6 8 9 = 23
70: 6 50 100 = 156
75: 1 10 50 = 61
80: 80 100 4 = 184
85: 50 1 2 = 53
90: 70 30 2 = 102
95: 40 6 70 = 116
100: 50 10 2 = 62
105: 40 70 30 = 140
110: 300 10 40 = 350
115: 30 200 2 = 232
Total: 3753
Take every 6th Letter and its immediate neighbours:
6: 1 10 5 = 16
12: 5 6 5 = 16
18: 8 6 40 = 54
24: 6 50 1 = 57
30: 80 10 40 = 130
36: 8 60 4 = 72
42: 400 50 90 = 540
48: 4 30 1 = 35
54: 40 50 300 = 390
60: 50 6 80 = 136
66: 8 9 1 = 18
72: 100 5 30 = 135
78: 100 5 80 = 185
84: 6 50 1 = 57
90: 70 30 2 = 102
96: 6 70 30 = 106
102: 2 50 10 = 62
108: 300 30 300 = 630
114: 70 30 200 = 300
Total: 3041
The totals from the letters of the Tetragrammaton together: 1746 + 3753 + 3041 = 8540 = 2 x 2 x 5 x 7 x 61 SF: 77 = 11 x 7. This parallels what was found for the words. (Unfortunately, when all four sums of the Tetragrammaton are used, they do not yield a result: 12293 = 19 x 647.)
In this feature, the name of the lord, the factors from the structure of the passage, and Revelation 1:8 all come together. If the feature applied only to the words, we might attribute this to coincidence. But it works also with the letters. Surely this means the Divine Name is written into the very structure of Exodus 34:6-7.
77.1The sum of all words ending with odd valued letters: 317 26 26 351 29 161 31 165, is 1106 = 79 x 7 x 2. This means the sum of all words ending with an even valued letter would be 6174 - 1106 = 5068 = 2 x 2 x 7 x 181.
77.2The sum of all words beginning with an odd valued letter: 792 = 2 x 2 x 2 x 3 x 3 x 11.
The sum of all words beginning with an even valued letter: 6174 - 792 = 5382 = 2 x 3 x 3 x 13 x 23.
77.2 is not divisible by 7 or 13, but it is not a total failure. The factor of 11 reminds us of the one God (beginning and end). The three factors of 2 mirror the paired attributes in Revelation 1:8, while the two factors of 3 represent the first and second parts of Revelation, each with attributes of three.
The final part of 77.2 contains the factor of God’s Name.
78.1Word sums where their digits added together is divisible by 7:
Word Position: 12 27 31 32 33 Word sum: 340 106 680 106 322
Total: 1554 = 2 x 3 x 7 x 37
78.2Seven (1 in 7) word sums in Exodus 34:6-7, when divided by the number 7, have a remainder of 1 (the one God). This automatically means the sum of these seven words is also divisible by 7.
6 15 17 18 27 31 32 120 351 456 29 106 680 106
Total: 1848 = 11 x 7 x 3 x 2 x 2 x 2.
79.The first letter is 6. The longest word in the passage has 6 letters. The number six is also special in that any positive integer equal or less than it produces a chain of factors eventually leading back to six (see Appendix). Given these unique reasons, the following two tables list six letters beginning with the first and last letters of each word.
Table 79.1.1
Six letters starting from the beginning of each word
(counting forwards).
Column Row
Row I II III IV V VI Total
I 6 10 100 200 1 10 327
II 10 5 6 5 10 5 41
III 10 5 6 5 1 30 57
IV 1 30 200 8 6 40 285
V 200 8 6 40 6 8 268
VI 6 8 50 6 50 1 121
VII 1 200 20 1 80 10 312 = 8 x 3 x 13
VIII 1 80 10 40 6 200 337
IX 6 200 2 8 60 4 280 = 8 x 5 x 7
X 8 60 4 6 1 40 119 = 7 x 17
XI 6 1 40 400 50 90 587
XII 50 90 200 8 60 4 412
XIII 8 60 4 30 1 30 133 = 7 x 19
XIV 30 1 30 80 10 40 191
XV 50 300 1 70 6 50 477
XVI 70 6 50 6 80 300 512
XVII 6 80 300 70 6 8 470
XVIII 6 8 9 1 5 6 35 = 5 x 7
XIX 6 50 100 5 30 1 192
XX 30 1 10 50 100 5 196 = 4 x 7 x 7
XXI 10 50 100 5 80 100 345
XXII 80 100 4 70 6 50 310
XXIII 70 6 50 1 2 6 135
XXIV 1 2 6 400 70 30 509
XXV 70 30 2 50 10 40 202
XXVI 2 50 10 40 6 70 178
XXVII 6 70 30 2 50 10 168 = 8 x 3 x 7
XXVIII 2 50 10 2 50 10 124
XXIX 2 50 10 40 70 30 202
XXX 70 30 300 30 300 10 740
XXXI 300 30 300 10 40 6 686 = 2 x 7 x 7 x 7
XXXII 6 70 30 200 2 70 378 = 2 x 9 x 7
XXXIII 200 2 70 10 40 6 328
Total of column 1: 1330 = 2 x 5 x 7 x 19
2: 1743 = 3 x 7 x 83
3: 2070
4: 1899
5: 1295 = 5 x 7 x 37
6: 1320
Table total: 9657
Rows 9, 10, 13, 18, 20, 27, 31 and 32 are all divisible by 7. Columns 1, 2, and 5 are also divisible by 7. The sum of the number of rows and columns is 168 (2 x 2 x 2 x 3 x 7).
There are a total of 39 sums calculated from the rows and columns. Random chance would indicate perhaps 5 or 6 sums divisible by 7. This chart produced 11 sums divisible by 7, almost twice the number expected.
Table 79.1.2
Six letters beginning with the last letter of each word
(counting backwards).
Column Row
Row I II III IV V VI Total
I 1 200 100 10 6 40 357 = 3 x 7 x 17
II 5 6 5 10 1 200 227
III 5 6 5 10 5 6 37
IV 30 1 5 6 5 10 57
V 40 6 8 200 30 1 285
VI 50 6 50 8 6 40 160
VII 20 200 1 50 6 50 327
VIII 40 10 80 1 20 200 351 = 9 x 13
IX 2 200 6 40 10 80 338 = 2 x 13 x 13
X 4 60 8 2 200 6 280 = 8 x 5 x 7
XI 400 40 1 6 4 60 511 = 7 x 73
XII 200 90 50 400 40 1 781
XIII 4 60 8 200 90 50 412
XIV 40 10 80 30 1 30 191
XV 1 300 50 40 10 80 481 = 13 x 37
XVI 50 6 70 1 300 50 477
XVII 70 300 80 6 50 6 512
XVIII 5 1 9 8 6 70 99
XIX 5 100 50 6 5 1 167
XX 1 30 5 100 50 6 192
XXI 5 100 50 10 1 30 196 = 4 x 7 x 7
XXII 4 100 80 5 100 50 339
XXIII 50 6 70 4 100 80 310
XXIV 400 6 2 1 50 6 465
XXV 30 70 400 6 2 1 509
XXVI 40 10 50 2 30 70 202
XXVII 30 70 6 40 10 50 206
XXVIII 10 50 2 30 70 6 168 = 8 x 3 x 7
XXIX 40 10 50 2 10 50 162
XXX 30 70 40 10 50 2 202
XXXI 40 10 300 30 300 30 710
XXXII 30 70 6 40 10 300 456
XXXIII 40 10 70 2 200 30 352
Total of column 1: 1722 = 2 x 3 x 7 x 41
2: 2214
3: 1797
4: 1316 = 2 x 2 x 7 x 47
5: 1778 = 2 x 7 x 127
6: 1692
Table total: 10519
Rows 1, 10, 11, 21, 28 and columns 1, 4, 5 are all divisible by 7. The total of the rows and columns is 81. Unlike the previous table, the rows and columns do not add up to something divisible by 7. The number of sums divisible by 7 are just slightly more than the odds.
The total of the two tables together: 10519 + 9657 = 20176 = 2 x 2 x 2 x 2 x 13 x 97.
Letter 40 is the last letter of the proclamation, but it does not have unique supporting reasons like letter 6. No word in the verse is 40 letters long. No special mathematical features appear with this number on its own. Knowing this, we can expect to find fewer numeric features when the same technique is applied to this letter.
Beginning with the first letter of each word, record a total of 40 letters. The results for each word:
Table 79.2.1
1 1453
2 1884
3 1953 = 9 x 7 x 31
4 2087
5 2406
6 2279
7 2621
8 2418 = 2 x 3 x 13 x 31
9 2448
10 2276
11 2364
12 2106 = 2 x 81 x 13
13 1892
14 1829
15 2200
16 1965
17 1921
18 1537
19 1978
20 2173
21 2242
22 2359 = 7 x 337
23 2231
24 2406
25 2023 = 7 x 17 x 17
26 1938
27 1878
28 1986
29 1978
30 1983
31 2103
32 1560 = 8 x 3 x 5 x 13
33 1664 = 8 x 8 x 2 x 13
Only 3 rows out of the 33 are divisible by 7, which is less than the odds. The grand total of the entire table: 68141 (no feature).
Of the forty columns, only seven are divisible by 7. This is not much better than the odds would dictate. They are:
Column 1: 1330 = 2 x 5 x 7 x 19
2: 1743 = 3 x 7 x 83
5: 1295 = 5 x 7 x 37
7: 2415 = 3 x 5 x 7 x 23
16: 1617 = 3 x 7 x 7 x 11
21: 2275 = 5 x 5 x 7 x 13
37: 1400 = 2 x 2 x 2 x 5 x 5 x 7
The sum of the rows and columns divisible by 7 together: 141 (no feature).
Beginning with the end of each word, record 40 letters (counting backwards). The results for each word:
Table 79.2.2
1 2406
2 2023 = 7 x 17 x 17
3 1897 = 7 x 271
4 1878
5 2024
6 2022
7 2103
8 1594
9 1686
10 1526 = 2 x 7 x 109
11 1847
12 1877
13 1933
14 2087
15 2207
16 2279
17 2665 = 5 x 13 x 41
18 2422 = 2 x 7 x 173
19 2447
20 2276
21 2363
22 2106 = 2 x 3 x 3 x 3 x 3 x 13
23 1892
24 2199
25 2268 = 2 x 2 x 3 x 3 x 3 x 3 x 7
26 2190
27 1925 = 5 x 5 x 7 x 11
28 1925 = 5 x 5 x 7 x 11
29 1571
30 1654
31 2172
32 2242
33 2319
Seven rows out of 33 are divisible by 7 (rows: 2, 3, 10, 18, 25, 27, 28). This is better than the odds.
Seven columns are also divisible by 7.They are,
columns 1: 1722
4: 1316
5: 1778
23: 1442
35: 1435
37: 1428
39: 1379
The rows and columns together add up to 257 (no feature). The grand total of table 75.2.2 is 68025 (no feature).
The letter 6 has three intrinsic features: 1) It is the first letter of the proclamation. 2) It has mathematical uniqueness (see Appendix). 3) It has a relationship to the longest word in the passage. The letter 40 only has one intrinsic quality: it is the last letter of the passage. As a result, letter 6 produced more features in total than letter 40. This matches our initial expectation. But there is another parallel.
Note how the letter 6 (which is at the beginning of the passage), produced more features in the first table (counting from the beginning of each word). And note how the letter 40 (which is at the end of the verse), produced more features in the second table (working from the end of each word).
80.The features in this study confirm Exodus 34:6-7 was numerically designed. But is there another form of design
? Internet packets and cd-roms were designed to have check sums for error correction. Does the proclamation exhibit this type of design? In a way, yes. However, since this is dealing with language, it would be unreasonable to expect something very structured and in-depth as with modern computer technology.
What type of error correction
might there be? The simplest would be something that confirmed the number of letters, the number of words, or the sum total of Exodus 34:6-7. And what might the check number
be? At a guess, there would be a relationship to either the number 13 or 7.
We begin at the beginning for two reasons: 1) Revelation 1:8 and 2) The beginning and the end are the two most obvious places to put a check sum.
The declaration begins with the letter 6, and ends with the letter 40. The total is 46. And we quickly notice: 46 - 13 = 33. There are 33 words in the passage.
Now if the first and last letters confirm the words, then the first and last words might corroborate the number of letters.
The first word is 317, and the last word is 322.
The total is 639. This time, 639 - 520 = 119.
There are 119 letters in the verses. (520 is 40 x 13.)
We can re-write the results as: 46 - (13 x 1) = 33, and
639 - (13 x 40) = 119 (The reason for this is given below.)
[In the first part of this study, the number of words, letters, and the sum of the passage all had features which correlated with the meaning of Revelation 1:8. The same can be said of the sum of the first and last words of the proclamation. 639 = 3 x 3 x 71. The pair of threes emphasizes Alpha and Omega
, First and Last
, Beginning and End
, and is, was, is to come
. The digits of 71 can almost be read out as the perfect one.
]
The first and last letters and words thus far have been used separately. They can be used together to verify the sum total of the passage.
46 + 639 = 685. This isn't anywhere near the sum of the proclamation. At this point, only the value of the words and letters of the first and last word have been used. What other information can be gleaned from the first and last words? The two words together have 10 letters.
Thus: 685 x 10 = 6850.
And: 6850 - (13 x 52) = 6174 (the sum of the proclamation).
By using words and letters from the beginning and end of the passage, along with various multiples of 13, it is possible to check the total number of letters, words and the sum of the passage.
To ensure this is not simply some sort of fluke, the coefficients of 13 can be cross checked.
Coefficients of 13 as a,
letter position: 1 40 52
Letter found: 6 40 10
The sum of the letters found: 56 = 7 x 2 x 2 x 2. SF13.
Coefficient used to count
letter positions: 1 41 93
Letter found: 6 400 10 = 416 = 13 x 2 x 2 x 2 x 2 x 2.
Does Exodus 34:6-7 contain some sort of check sum? The above is not exactly proof of this type of construction, but the possibility exists.
81.There are many minor mathematical curiosities that apply to Exodus 34:6b-7. They are labelled curious
and coincidental, since they have no religious meaning or connection. Their only plus is that they produce numeric features. Three are presented below.
81.1The sum of every 7th letter is 465. The sum of every 22nd letter is 669. Alone, these two do not produce any features, but they do together. 465 + 669 = 1134 (7 x 3 x 3 x 3 x 3 x 2). SF: 21 (7 x 3). But why should the 7th and 22nd letters be put together? There are 22 letters in the Hebrew alphabet. We combine it with the number associated with God’s perfection. But there may also be a mathematical reason. 22 and 7 are the smallest whole numbers that give the closest approximation of Pi as a ratio.
81.2Applying a geometric sequence: 1 2 4 8 16 32 64. The sequence stops at the seventh term since there is no 128th position.
1 2 4 8 16 32 64 6 10 200 6 200 6 6
Total: 434 = 2 x 7 x 31
81.3The very first word (a total of 317) of the passage begins with the letter 6 and ends with the letter 1. Find the next word that begins with a letter 1. This is the fourth word (total of 31). It ends with the letter 30. Find the next word that begins with letter 30. This is the fourteenth word (total of 191). This word ends with the letter 40. Since no word in the passage begins with the letter 40, this sequence ends. The total of these three words is 539 (11 x 7 x 7).
This can also be done with the last word of the passage. This word has a sum of 322. It begins with the letter 200, and ends with the letter 40. In essence, the sequence begins and ends with this one word. And of course, 322 is also divisible by 7 (2 x 7 x 23).
82.1Create larger word sums by inserting a zero after the first digit (e.g. 317 becomes 3017). When this is done, some words become divisible by 7. Some words, formerly divisible by 7, are no longer divisible by 7, while others have experience no change.
3017 206 206 301 2054 1020 2021 1031 2008 702 4047 3040 702 1091 3051 1026 4056 209 1061 301 1065 1084 1026 4009 1000 1002 1006 602 1002 1000 6080 1006 3022
The new total: 54054 = 2 x 3 x 3 x 3 x 7 x 11 x 13 SF:42 = 7 x 3 x 2
82.2Insert the digit 7 after the first digit.
3717 276 276 371 2754 1720 2721 1731 2708 772 4747 3740 772 1791 3751 1726 4756 279 1761 371 1765 1784 1726 4709 1700 1702 1706 672 1702 1700 6780 1706 3722
The sum: 72114 = 2 x 3 x 7 x 17 x 101 SF:130 = 13 x 5 x 2
82.3.1The factors in 82.1, and 82.2 contain the numbers 11 and 101, both pointing to the one God from beginning to end.
82.3.2The sum of the factors in one case is 42 (7 x 6), while the other is 130 (13 x 10).
82.3.4Inserting any other digit (1, 2, 3, 4, 5, 6, 8, or 9) after the first digit does not produce any features. Only 0 and 7 work. Naturally, 0 + 7 is still 7.
82.4.1Make larger word sums by inserting a 4 just before the last digit (e.g. 317 becomes 3147).
3147 246 246 341 2544 1240 2241 1341 2048 742 4447 3440 742 1941 3541 1246 4546 249 1641 341 1645 1844 1246 4049 1040 1042 1046 642 1042 1040 6840 1046 3242
Total: 62034 = 2 x 3 x 7 x 7 x 211
82.4.2Inserting a 7 just before the last digit:
3177 276 276 371 2574 1270 2271 1371 2078 772 4477 3470 772 1971 3571 1276 4576 279 1671 371 1675 1874 1276 4079 1070 1072 1076 672 1072 1070 6870 1076 3272
Total: 63024 = 2 x 2 x 2 x 2 x 3 x 13 x 101
82.4.34 and 7 is 11 (one God first and last).
Just as the first
is not the same as the last
, so feature 82.4 is not exactly the same as features 82.1 and 82.2.
83.The longest string of single digit
letters occurs between positions 63 (1:7) and 70 (1:7).
position 64 65 66 67 68 69 letters 6 8 9 1 5 6
83.1Sum of the positions: 399 = 3 x 7 x 19.
83.2Sum of the letters: 35 = 5 x 7.
83.3The letters run together as a large number: 689156 = 2 x 2 x 13 x 29 x 457
83.4.1Sum of the first and last position: 133 = 7 x 19
83.4.2Sum of the second and second last position: 133 = 7 x 19
83.4.3Sum of the inner pair: 133 = 7 x 19.
84.God chose the words and letters for His proclamation to demonstrate structure and design. The 119 letters of the passage have been arranged from least to greatest and put into a 7 x 17 table.
Column
1 2 3 4 5 6 7 Row
Row Totals
1 1 1 1 1 1 1 1 = 7
2 1 1 1 2 2 2 2
3 2 2 4 4 4 5 5 = 26 (2 x 13)
4 5 5 5 5 5 6 6
5 6 6 6 6 6 6 6 = 42 (2 x 3 x 7)
6 6 6 6 6 6 6 6 = 42 (2 x 3 x 7)
7 8 8 8 8 8 9 10
8 10 10 10 10 10 10 10 = 70 (2 x 5 x 7)
9 10 10 10 20 30 30 30 = 140 (2 x 2 x 5 x 7)
10 30 30 30 30 30 30 40
11 40 40 40 40 40 40 40 = 280 (2 x 2 x 2 x 5 x 7)
12 50 50 50 50 50 50 50 = 350 (2 x 5 x 5 x 7)
13 50 50 50 50 60 60 70 = 390 (2 x 3 x 5 x 13)
14 70 70 70 70 70 70 70 = 490 (2 x 5 x 7 x 7)
15 80 80 80 80 90 100 100
16 100 100 200 200 200 200 200
17 200 300 300 300 300 400 400
Column totals:
669 769 871 882 912 1025 1046
84.1Almost half of the seventeen rows are divisible by 7.
84.2The middle row is divisible by 7, as is the middle column.
84.3Seven of the rows contain only a single letter value. The 7th row contains only 70s.
84.4.1The 13th row is divisible by 13.
84.4.2Two out of the seventeen rows are divisible by 13, just as the passage contains the Name twice.
84.5The corners of the table total 602 (2 x 7 x 43).
85.Add up the letters one by one, noting the positions and letters where a total is divisible by 7. Reset the total to zero as each section is found.
a) letter positions, b) letter values, c) running total
Segment 1
a] 1 2 3 4 5 6 7 8 9 = 45 = 3 x 3 x 5
b] 6 10 100 200 1 10 5 6 5 = 343 = 7 x 7 x 7 c] 343 = 7 x 7 x 7
Segment 2
a] 10 11 12 = 33 = 3 x 11
b] 10 5 6 = 21 = 3 x 7 c] 364 = 2 x 2 x 7 x 13
Segment 3
a] 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31
b] 5 1 30 200 8 6 40 6 8 50 6 50 1 200 20 1 80 10 40
a] 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 = 1003
b] 6 200 2 8 60 4 6 1 40 400 50 90 200 8 60 = 1897
c] 2261 = 7 x 17 x 19
Segment 4
a] 47 48 49 = 144 = 2 x 2 x 2 x 2 x 3 x 3
b] 4 30 1 = 35 = 5 x 7
c] 2296 = 2 x 2 x 2 x 7 x 41
Segment 5
a] 50 51 52 53 54 = 260 = 2 x 2 x 5 x 13
b] 30 80 10 40 50 = 210 = 2 x 3 x 5 x 7 c] 2506 = 2 x 7 x 179
Segment 6 Segment 7
a] 55 56 = 111 = 3 x 37 a] 57 = 57 = 3 x 19
b] 300 1 = 301 = 7 x 43 b] 70 = 70 = 2 x 5 x 7
c] 2807 = 7 x 401 c] 2877 = 3 x 7 x 137
Segment 8
a] 58 59 = 117 = 3 x 3 x 13
b] 6 50 = 56 = 2 x 2 x 2 x 7
c] 2933 = 7 x 419
Segment 9
a] 60 61 62 63 64 = 310 = 2 x 5 x 31
b] 6 80 300 70 6 = 462 = 2 x 3 x 7 x 11 c] 3395 = 5 x 7 x 97
Segment 10
a] 65 66 67 68 69 70 71 72 73 74 75 76 77
b] 8 9 1 5 6 50 100 5 30 1 10 50 100
a] 78 79 80 = 1160 = 2 x 2 x 2 x 5 x 29
b] 5 80 100 = 560 = 2 x 2 x 2 x 2 x 5 x 7 c] 3955 = 5 x 7 x 113
Segment 11
a] 81 82 83 84 85 86 = 501 = 3 x 167
b] 4 70 6 50 1 2 = 133 = 7 x 19 c] 4088 = 2 x 2 x 2 x 7 x 73
Segment 12
a] 87 88 = 175 = 5 x 5 x 7
b] 6 400 = 406 = 2 x 7 x 29 c] 4494 = 2 x 3 x 7 x 107
Segment 13
a] 89 = 89 = 89
b] 70 = 70 = 2 x 5 x 7
c] 4564 = 2 x 2 x 7 x 163
Segment 14
a] 90 91 92 93 94 95 96 97 = 748 = 2 x 2 x 11 x 17
b] 30 2 50 10 40 6 70 30 = 238 = 2 x 7 x 17
c] 4802 = 2 x 7 x 7 x 7 x 7
Segment 15
a] 98 99 100 101 102 103 104 105 106 107 108 109 110 111
b] 2 50 10 2 50 10 40 70 30 300 30 300 10 40
a] 112 113 114 = 1802 = 2 x 17 x 53
b] 6 70 30 = 1050 = 2 x 3 x 5 x 5 x 7
c] 5852 = 2 x 2 x 7 x 11 x 19
Segment 16
a] 115 116 117 118 119 = 585 = 3 x 3 x 5 x 13
b] 200 2 70 10 40 = 322 = 2 x 7 x 23
c] 6174 = 2 x 3 x 3 x 7 x 7 x 7
First letters of each segment:
6 10 5 4 30 300 70 6 6 8 4 6 70 30 2 200 = 757
Last letters of each segment:
5 6 60 1 50 1 70 50 6 100 2 400 70 30 30 40 = 921
Positions of first letters of each segment:
1 10 13 47 50 55 57 58 60 65 81 87 89 90 98 115 = 976
Positions of last letters of each segment:
9 12 46 49 54 56 57 59 64 80 86 88 89 97 114 119 = 1079 (13 x 83)
85.1Applying Revelation 1:8, we examine the beginning and end segments.
85.1.1Letter positions of the first and last segments: 630 (2 x 3 x 3 x 5 x 7).
85.1.2The first and last segments together have 14 letters (7 x 2).
85.1.3Applying is, was, and is to come
to the first segment, this makes the last segment the segment that was
before, and the second segment, the one to come
.
The total of the letters in the first, second and last segments: 686 = 7 x 7 x 7 x 2 (SF:23)
The total of the positions in the first, second and last segments: 663 = 3 x 13 x 17 (SF:33)
85.1.4Applying is, was, and is to come
to the last segment, this makes the second last segment the segment that was
before, and the first segment, the one to come
.
Total of the letters in the last, second last, and first segments: 1715 = 7 x 7 x 7 x 5 (SF:26 = 13 x 2).
Total of the positions in the last, second last, and first segments: 2432 = 2 x 2 x 2 x 2 x 2 x 2 x 2 x 19 (SF:33)
The symmetry only breaks down in the last feature, but even here, there is something. The sum of the factors matches the sum of the factors for the positions in 85.1.3.
85.2The second and second last segments have a letter total of 1414 (2 x 7 x 101). In the total we see the same number divisible by 7 in the first and last halves. In the factors, we see the one God beginning and end.
85.3We can also use Revelation 1:8's suggestion of magnitude (first and last). In this case, magnitude can be the longest and shortest segments.
85.3.1The longest is the third segment from the beginning. The shortest is the fourth section from the end of the passage. (3 + 4 = 7). (There is an equally short section, but it is not at the proclamation's end.)
85.3.2The sum of the letter positions in the longest and shortest segments is 1092 (2 x 2 x 3 x 7 x 13).
85.3.3The longest section has 34 letters, while the shortest section has only 1 letter. Together, long and short, the total would be 35 letters (7 x 5).
85.3.4The running total at the longest section is 2261, while the running total at shortest section is 4564. The running totals together: 6825 = 3 x 5 x 5 x 7 x 13 (YHWH).
85.3.5First and last in magnitude could also refer to the letter totals, rather than the longest and shortest segments. The segments with the highest and lowest letter totals are right next to each other (segments 2 and 3). The sum of the letter positions is 1036 = 37 x 7 x 2 x 2.
85.4.1The 7th segment is the first with a single letter 70. The running total is 2877, which factors 3 x 7 x 137. The sum of these factors is 147 (7 x 7 x 3).
85.4.2The 13th segment (number relates to the Name) is the next section with a single letter 70.
85.5The 14th segment (7 x 2, and four
teen) is the only one with a running total containing four
factors of 7: 4802 = 7 x 7 x 7 x 7 x 2.
85.6.1Three segments have position totals divisible by 13.
Segment: 5 8 16
260 117 585
The total of these three segments is naturally divisible by 13, but the sum of the factors goes one step further: 962 = 37 x 13 x 2 (SF:52 = 13 x 2 x 2).
85.6.2The letter totals of these segments exhibit a similar feature.
Segment: 5 8 16
210 56 322
The sum of the letters goes one step deeper: 588 = 7 x 7 x 3 x 2 x 2 (SF:21 = 7 x 3).
85.7Only the position total in the 12th segment is divisible by 7. And yet, when the position totals are considered together, something new appears.
a) List of segments b) Position totals of segments a) 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 b) 45 33 1003 144 260 111 57 117 310 1160 501 175 89 748 1802 585 Odd positioned segments: 45 1003 260 57 310 501 89 1802
85.7.1The total is: 4067 = 7 x 7 x 83.
Even positioned segments
33 144 111 117 1160 175 748 585
85.7.2The total is: 3073 = 7 x 439.
86.Rather than add up letters searching for totals divisible by 7, how about searching for totals divisible by 13? Now the number 7 correlates to the actual structure of the proclamation. The sum of the passage is divisible by 7, and there are 119 letters, which is also divisible by 7. The number 13 does not fit the structure of the passage like the number 7, but it is a factor of God’s Name. Because this is not a perfect fit
we should not expect as many features as in the previous case. And as 13 is not 7, so the features will not be the same.
There are six sections as opposed to the sixteen in the previous feature and the last segment ends before the close of the verse.
a) Letter position. b) Letter value. c) Running total. Segment 1 a) 1 2 3 4 5 6 7 8 = 36 = 2 x 2 x 3 x 3 b) 6 10 100 200 1 10 5 6 = 338 = 2 x 13 x 13 c) 338 = 2 x 13 x 13 Segment 2 a) 9 10 11 12 = 42 = 2 x 3 x 7 b) 5 10 5 6 = 26 = 2 x 13 c) 364 = 2 x 2 x 7 x 13 Segment 3 a) 13 14 15 16 17 18 19 20 21 22 23 24 25 26 = 273 = 3 x 7 x 13 b) 5 1 30 200 8 6 40 6 8 50 6 50 1 200 = 611 = 13 x 47 c) 975 = 3 x 5 x 5 x 13 Segment 4 a) 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 b) 20 1 80 10 40 6 200 2 8 60 4 6 1 40 400 50 90 200 8 a) 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 b) 60 4 30 1 30 80 10 40 50 300 1 70 6 50 6 80 300 70 a) 64 65 66 67 68 69 70 71 72 73 74 75 76 77 b) 6 8 9 1 5 6 50 100 5 30 1 10 50 100 a) 2652 = 2 x 2 x 3 x 13 x 17 b) 2795 = 5 x 13 x 43 c) 3770 = 2 x 5 x 13 x 29 Segment 5 a) 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 b) 5 80 100 4 70 6 50 1 2 6 400 70 30 2 50 10 40 6 70 a) 97 98 99 100 101 102 103 104 = 2457 = 3 x 3 x 3 x 7 x 13 b) 30 2 50 10 2 50 10 40 = 1196 = 2 x 2 x 13 x 23 c) 4966 = 2 x 13 x 191 Segment 6 a) 105 106 107 108 109 110 111 = 756 = 2 x 2 x 3 x 3 x 3 x 7 b) 70 30 300 30 300 10 40 = 780 = 2 x 2 x 3 x 5 x 13 c) 5746 = 2 x 13 x 13 x 17
86.1The position total of the letters of these six segments are either divisible by 7 or 13. Only the very first segment has a position total not divisible by 7 or 13. This lack is compensated by the total of the letters: 338. 338 is divisible by 13 twice.
86.2.1The first letter of each segment: 6 5 5 20 5 70 = 111. The one God who was, is and is to come.
86.2.2The last letter of each segment: 6 6 200 100 40 40 = 392 (2 x 2 x 2 x 7 x 7). Here we see God’s perfection doubled, and the paired attributes: Alpha and Omega, Beginning and End, First and Last.
86.3The position total of the first letters of each word yield no feature: 1 9 13 27 78 105 = 233. Again to make up for it, the position total of the last letters of each segment yields two thirteens: 8 12 26 77 104 111 = 338 (2 x 13 x 13). This is the second time 338 appears.
86.4The running total of the first and last segments are both divisible by 13 twice.
86.5The shortest and longest segments are also a type of first and last. Two totals divisible by 13 come together producing one divisible by 7. The total of the letters in segments 2 and 4 is 2821 (7 x 13 x 31).
86.6The information of the first and last segments can be combined.
Segment: 1 6 Position total: 36 756 Letter total: 338 780 Running total: 338 5746
86.6.1Sum of the segment positions: 1 + 6 = 7.
86.6.2Sum of the position totals: 36 + 756 = 792 (2 x 2 x 2 x 3 x 3 x 11). The factors match Revelation 1:8 marvellously. The triplet of 2s are the three sets of paired attributes. The pair of 3s represents the first and second parts of Revelation 1:8, and the 11 is a visual representation of the one God beginning and end.
86.6.3Sum of the running totals: 338 + 5746 = 6084 (2 x 2 x 3 x 3 x 13 x 13). The divine factor appears twice.
Only the sum of the letter totals fails to yield anything new.
Could all the features here be coincidence? This section does not have Part I's hallmark. There is no outside verse providing rules or reasons to support it. If this segment stood alone, it would be much weaker, but it does not. The conclusion after Part III will show how all three parts fit a greater design.
God has arranged all this with such care you can be certain there is even more in the meaning of the text. Read it and study it. Don't miss out on the great lessons in the Bible just by concentrating on the numbers.