Alpha & Omega
The description of God in Revelation 1:8 is of complementary opposites. God claims to be Alpha and Omega. Elsewhere, He also says He is First and Last (Isaiah 44:6). This can be applied in many ways to the words and letters of The Proclamation (Exodus 34:6-7).
The word values from The Proclamation are listed below.
List of words: 317 26 26 31 254 120 221 131 208 72 447 340 72 191 351 126 456 29 161 31 165 184 126 409 100 102 106 62 102 100 680 106 322
1Since Alpha and Omega (or First and Last) are two characteristics of God, look for word values that appeared more than once.
1.0There are exactly seven of them: 26, 31, 72, 100, 102, 106, and 126. (No word value appeared more than two times.) These seven word values represent seven possible tries at finding a numeric feature. The odds would predict one of them succeeding, but there are actually two successes.
1.1.1Word value 102 appears as the 26th and 29th words of the passage. The 26th position is its first appearance. The 29th position is its last appearance. If the first appearance is considered as Alpha, and nothing can be before Alpha, then everything from the beginning of the passage up to and including the 26th word should also be considered a part of Alpha. Similarly, everything from the end of the passage up to and including the 29th word is a part of Omega.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 317 26 26 31 254 120 221 131 208 72 447 340 72 191 351 126 456 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 29 161 31 165 184 126 409 100 102 106 62 102 100 680 106 322
Alpha and Omega together produce a very symmetrical 6006 (2 x 3 x 7 x 11 x 13).
1.1.2This leaves two words in between the values of 102: 106 62 = 168 (23 x 3 x 7). One could say, first and last appearances of word value 102 distinguish what is outside and inside.
1.2The other word value that sets apart outside and inside is the word value 26 from God’s name.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 317 26 26 31 254 120 221 131 208 72 447 340 72 191 351 126 456 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 29 161 31 165 184 126 409 100 102 106 62 102 100 680 106 322
1.2.1Since this is from God’s name, there are extra features. The Alpha section: 317 + 26 = 343 = 73.
1.2.2The Omega section: 5831 = 73 x 17.
1.2.3Since both words valued 26 are back to back, there is nothing in between them. As Alpha, God is eternal before our world. As Omega, God is eternal after our world. The finite history of our world is nothing in light of eternity.
1.3As mentioned previously, there were seven word values that had more than one appearance. The odds would suggest only one being able to produce a numeric feature divisible by 7. What we found were two. Although this is twice the odds it could be coincidence. But was it coincidence when one of the word values came from God’s name? Is it coincidence when 102 and 26 together total 128? 128 is not divisible by 7 or 13, but 128 is 27.
2.1The technique above also works with the letters, demonstrating that this is not freaky chance.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 6 10 100 200 1 10 5 6 5 10 5 6 5 1 30 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 200 8 6 40 6 8 50 6 50 1 200 20 1 80 10 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 40 6 200 2 8 60 4 6 1 40 400 50 90 200 8 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 60 4 30 1 30 80 10 40 50 300 1 70 6 50 6 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 80 300 70 6 8 9 1 5 6 50 100 5 30 1 10 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 50 100 5 80 100 4 70 6 50 1 2 6 400 70 30 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 2 50 10 40 6 70 30 2 50 10 2 50 10 40 70 106 107 108 109 110 111 112 113 114 115 116 117 118 119 30 300 30 300 10 40 6 70 30 200 2 70 10 40
2.1.1The 34th letter is the first appearance of letter value 2. The Alpha letters: 1334.
2.1.2The 116th letter is the last appearance of letter value 2. The Omega letters: 122.
2.1.3Alpha and Omega together: 1456 = 24 x 7 x 13. SF: 28 = 22 x 7.
2.1.4The letters between Alpha and Omega: 4718 = 2 x 7 x 337.
2.2Letter value 6 is the next where this technique is true.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 6 10 100 200 1 10 5 6 5 10 5 6 5 1 30 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 200 8 6 40 6 8 50 6 50 1 200 20 1 80 10 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 40 6 200 2 8 60 4 6 1 40 400 50 90 200 8 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 60 4 30 1 30 80 10 40 50 300 1 70 6 50 6 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 80 300 70 6 8 9 1 5 6 50 100 5 30 1 10 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 50 100 5 80 100 4 70 6 50 1 2 6 400 70 30 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 2 50 10 40 6 70 30 2 50 10 2 50 10 40 70 106 107 108 109 110 111 112 113 114 115 116 117 118 119 30 300 30 300 10 40 6 70 30 200 2 70 10 40
2.2.1The first letter is the first appearance of 6. Alpha letter: 6.
2.2.2The last appearance of letter 6 is in the 112th position. Omega letters: 428.
2.2.3Alpha and Omega: 434 = 2 x 7 x 31. (This is a very nice symmetrical number with the first two digits adding to seven, and the last two digits also adding to seven.)
2.2.4The letters between Alpha and Omega: 5740 = 22 x 5 x 7 x 41.
2.3Letter value 300 is the last letter where this technique is true.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 6 10 100 200 1 10 5 6 5 10 5 6 5 1 30 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 200 8 6 40 6 8 50 6 50 1 200 20 1 80 10 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 40 6 200 2 8 60 4 6 1 40 400 50 90 200 8 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 60 4 30 1 30 80 10 40 50 300 1 70 6 50 6 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 80 300 70 6 8 9 1 5 6 50 100 5 30 1 10 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 50 100 5 80 100 4 70 6 50 1 2 6 400 70 30 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 2 50 10 40 6 70 30 2 50 10 2 50 10 40 70 106 107 108 109 110 111 112 113 114 115 116 117 118 119 30 300 30 300 10 40 6 70 30 200 2 70 10 40
2.3.1The Alpha letters: 2806.
2.3.2The Omega letters: 778.
2.3.3Alpha and Omega: 3584 = 29 x 7.
2.3.4The letters between Alpha and Omega: 2590 = 2 x 5 x 7 x 37.
2.4It must be remembered that there were many letters that appeared multiple times in the passage.
Letter: 1 2 4 5 6 8 9 10 20 30 40 50 60 70 80 90 100 200 300 400 Appearances: 10 6 3 7 16 5 1 11 1 9 8 11 2 8 4 1 4 6 4 2
Seventeen letters appeared more than once. That means there were 17 tries at finding one that might be divisible by 7. The odds would favour two successes, and possibly three. With letters 2, 6, and 300, there were three successes. This is the higher end of the odds, but not improbable. What makes it improbable and unlikely to be coincidence is because 2, 6 and 300 total 308 (22 x 7 x 11). This is exactly like the words.
2.4.1Unlike the words, the positions of these letters have an additional feature. Their first and last appearances are listed below.
Letter value: 2 2 6 6 300 300 Position: 34 116 1 112 55 109
Total of the positions: 427 = 7 x 61.
2.4.2The very first position of these six letters, and the very last position show something else: 34 + 109 = 143 (11 x 13).
2.4.3The total of the three first positions is 90. The total of the three last positions is 337. The difference between the first and last positions: 247 = 13 x 19.
2.5If the charts from 2.1, 2.2, and 2.3 were laid on top of each other, only the letter 6 would be in all the grey Alpha zones. Only the last four letters, 2, 70, 10, and 40 would be in all the green Omega zones. The total of these common letters: 128 (27). This is like feature 1.3 where the words also produced the same number.
The features above were discovered by adhering strictly to the rule of the very first and very last appearances of a word or letter value. The next features fall in a new category where the rule is extended to the Nth and Nth last appearances. Random chance would expect only some letters to succeed, and that there would be no relationship between letters that succeed. Random chance is wrong. There is a relationship.
2.6The letter 6 appeared in the passage the most at sixteen times. If one paired these letters according to their Nth and Nth last appearances, there would be eight pairs. Of these eight pairs, the odds would mean one or perhaps two of them would produce a feature divisible by 7. We have already seen one success in feature 2.2. There are two others, and once again this pushes it slightly beyond the odds.
2.6.1The third and third last appearance of the letter 6.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 6 10 100 200 1 10 5 6 5 10 5 6 5 1 30 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 200 8 6 40 6 8 50 6 50 1 200 20 1 80 10 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 40 6 200 2 8 60 4 6 1 40 400 50 90 200 8 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 60 4 30 1 30 80 10 40 50 300 1 70 6 50 6 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 80 300 70 6 8 9 1 5 6 50 100 5 30 1 10 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 50 100 5 80 100 4 70 6 50 1 2 6 400 70 30 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 2 50 10 40 6 70 30 2 50 10 2 50 10 40 70 106 107 108 109 110 111 112 113 114 115 116 117 118 119 30 300 30 300 10 40 6 70 30 200 2 70 10 40
2.6.1.1The total of both sections: 2450 = 2 x 52 x 72 SF: 26 = 2 x 13.
2.6.1.1The total under the grey section: 364 = 22 x 7 x 13.
2.6.1.2The total under the green section: 2086 = 2 x 7 x 149.
2.6.1.3The total between the two sections: 3724 = 22 x 72 x 19.
2.6.2The fifth and fifth last appearances of the letter 6.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 6 10 100 200 1 10 5 6 5 10 5 6 5 1 30 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 200 8 6 40 6 8 50 6 50 1 200 20 1 80 10 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 40 6 200 2 8 60 4 6 1 40 400 50 90 200 8 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 60 4 30 1 30 80 10 40 50 300 1 70 6 50 6 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 80 300 70 6 8 9 1 5 6 50 100 5 30 1 10 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 50 100 5 80 100 4 70 6 50 1 2 6 400 70 30 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 2 50 10 40 6 70 30 2 50 10 2 50 10 40 70 106 107 108 109 110 111 112 113 114 115 116 117 118 119 30 300 30 300 10 40 6 70 30 200 2 70 10 40
2.6.2.1The total of both sections: 3416 = 23 x 7 x 61.
2.6.2.2The total between the two sections: 2758 = 2 x 7 x 197.
The individual sections have no features on their own. They have to be combined. One reason might be that the fifth and fifth last are moving further and further away from being the actual first and last.
2.7The letter 1 appeared ten times in the passage. This means the letter 1 could be paired Nth and Nth last five times. The odds are very much in favour of one pair producing a feature divisible by 7. It just so happens to be the very last pair, the fifth and fifth last appearances.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 6 10 100 200 1 10 5 6 5 10 5 6 5 1 30 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 200 8 6 40 6 8 50 6 50 1 200 20 1 80 10 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 40 6 200 2 8 60 4 6 1 40 400 50 90 200 8 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 60 4 30 1 30 80 10 40 50 300 1 70 6 50 6 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 80 300 70 6 8 9 1 5 6 50 100 5 30 1 10 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 50 100 5 80 100 4 70 6 50 1 2 6 400 70 30 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 2 50 10 40 6 70 30 2 50 10 2 50 10 40 70 106 107 108 109 110 111 112 113 114 115 116 117 118 119 30 300 30 300 10 40 6 70 30 200 2 70 10 40
2.7.1Total of both sections: 5292 = 22 x 33 x 72.
2.7.2Total of the section in between: 882 = 2 x 32 x 72.
2.7.3Providentially, letter 1 and letter 6 are the only two letters where their fifth and fifth last appearances produce a total divisible by 7. Why these two? Perhaps because 1 and 6 is 7.
2.8Two other letters stand together like the letters 1 and 6. These are the letters 10 and 200.
2.8.1The second and second last appearances of the letter 10.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 6 10 100 200 1 10 5 6 5 10 5 6 5 1 30 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 200 8 6 40 6 8 50 6 50 1 200 20 1 80 10 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 40 6 200 2 8 60 4 6 1 40 400 50 90 200 8 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 60 4 30 1 30 80 10 40 50 300 1 70 6 50 6 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 80 300 70 6 8 9 1 5 6 50 100 5 30 1 10 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 50 100 5 80 100 4 70 6 50 1 2 6 400 70 30 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 2 50 10 40 6 70 30 2 50 10 2 50 10 40 70 106 107 108 109 110 111 112 113 114 115 116 117 118 119 30 300 30 300 10 40 6 70 30 200 2 70 10 40
2.8.1.1Total of both groups: 805 = 5 x 7 x 23. SF: 35 = 5 x 7.
2.8.1.2Total of the letters between the two groups: 5369 = 7 x 13 x 59.
2.8.2The second and second last appearances of the letter 200.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 6 10 100 200 1 10 5 6 5 10 5 6 5 1 30 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 200 8 6 40 6 8 50 6 50 1 200 20 1 80 10 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 40 6 200 2 8 60 4 6 1 40 400 50 90 200 8 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 60 4 30 1 30 80 10 40 50 300 1 70 6 50 6 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 80 300 70 6 8 9 1 5 6 50 100 5 30 1 10 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 50 100 5 80 100 4 70 6 50 1 2 6 400 70 30 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 2 50 10 40 6 70 30 2 50 10 2 50 10 40 70 106 107 108 109 110 111 112 113 114 115 116 117 118 119 30 300 30 300 10 40 6 70 30 200 2 70 10 40
2.8.2.1Total of the two groups: 4781 = 7 x 683.
2.8.2.2Total of the letters in between: 1393 = 7 x 199.
2.8.3Why is it the second and second last appearances of the letters 10 and 200 that work? Perhaps because 10 and 200 equals 210 (2 x 3 x 5 x 7).
2.9In feature 2.7.3, it was the fifth and fifth last appearances of the letters 1 and 6. In feature 2.8.3 it was the second and second last appearances of the letters 10 and 200. This is very providential, because 5 and 2 is 7. It could have been the first, third, or fourth.
3Previously, we have seen the first and last letters of each word adding up to multiples of 7. Borrowing from the technique above, one could look at the second and second last letters of each word, the third and third last, the fourth, the fifth and the sixth. The search stops with the sixth because no word in the passage has more than six letters. As the shortest word in The Proclamation is only two letters, the search for any Nth letter more than two wraps around to the beginning, and the search for any Nth last letter greater than two wraps around to the end.
No results can be found for the second and second last letters of each word, the third and third last, fourth, or fifth. The only one that produces a result is the very last try, the sixth and sixth last letters.
3.1Total of the 6th and 6th last letters of each word: 2723 = 7 x 389.
3.2The 6th letter of each word (wrapping around at the end):
a) 1 2 2 2 2 1 3 2 3 3 2 3 3 6 3 3 2 1 2 2 2 3 3 2 2 2 b) 6 5 5 30 8 6 20 80 2 4 1 200 4 40 1 50 80 6 50 1 50 4 50 2 30 50 a) 3 3 2 2 1 3 1 (Effective letter position in word.) b) 30 10 50 30 300 30 200 (Letter value.)
Letter total: 1435 = 5 x 7 x 41.
3.3The 6th letter from the end of each word (again wrapping around the beginning):
a) 5 3 3 1 3 5 1 3 1 1 3 1 1 1 1 1 3 5 3 1 3 1 1 3 b) 1 6 6 1 6 50 1 10 6 8 40 50 8 30 50 70 300 5 100 30 100 80 70 6 a) 1 3 1 1 3 1 5 1 5 (Effective letter position in word.) b) 70 10 6 2 10 70 40 6 40 (Letter value.)
Letter total: 1288 = 23 x 7 x 23.
Thus, the first letter of each word, and the sixth letter of each word both worked whether counting from the beginning or the end. These are the only two that work because 1 + 6 = 7.
At first look, or even a second or deeper look, the placement of the letters would seem to be random and controlled only by the words in which they sit for the sentence. However, in applying Alpha and Omega hidden relationships appear. Is this still chance? Given the source of Exodus 34:6-7, and all the other features accumulating, this is highly unlikely. It could only have been designed this way.